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SOLVED:Show that the function f(x)=x^2 / 3 does not satisfy the hypotheses of the mean value theorem on [-1,27] but that nevertheless there is a number c in (-1,27) such that f^'(c)=(f(27)-f(-1))/(27-(-1))
2021年5月23日
numerade.com
SOLVED:Verify that the hypotheses of the Mean-Value Theorem are satisfied on the given interval, and find all values of c in that interval that satisfy the conclusion of the theorem. f(x)=√(25-x^2) ;[-5,3]
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(a) Use the Mean-Value Theorem to show that √(y)-√(x)<(y-x)/(2 √(x)) if 0< x <y. (b) Use the result in part (a) to show that if 0<x<y, then √(x y)<(1)/(2)(x+y). | Numerade
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use the graph of f to estimate the values of c that satisfy the conclusion of the mean value theorem for the interval 08 j fu 50271
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